Video Streaming with Socket programming

Kunal Maheshwari
2 min readJun 12, 2021

In this article I’ve shown Using Python socket programming to create Video streaming app using TCP stream.

Here’s the client.py code:

import socket,cv2, pickle,struct# create socket
client_socket = socket.socket(socket.AF_INET,socket.SOCK_STREAM)
host_ip = '192.168.29.78' # paste your server ip address here
port = 9999
client_socket.connect((host_ip,port)) # a tuple
data = b""
payload_size = struct.calcsize("Q")
while True:
while len(data) < payload_size:
packet = client_socket.recv(4*1024) # 4K
if not packet: break
data+=packet
packed_msg_size = data[:payload_size]
data = data[payload_size:]
msg_size = struct.unpack("Q",packed_msg_size)[0]

while len(data) < msg_size:
data += client_socket.recv(4*1024)
frame_data = data[:msg_size]
data = data[msg_size:]
frame = pickle.loads(frame_data)
cv2.imshow("RECEIVING VIDEO",frame)
key = cv2.waitKey(1) & 0xFF
if key == ord('q'):
break
client_socket.close()

And Here is the server.py code

import socket, cv2, pickle,struct# Socket Create
server_socket = socket.socket(socket.AF_INET,socket.SOCK_STREAM)
#host_name = socket.gethostname()
host_ip = '0.0.0.0'
print('HOST IP:',host_ip)
port = 9999
socket_address = (host_ip,port)
# Socket Bind
server_socket.bind(socket_address)
# Socket Listen
server_socket.listen(5)
print("LISTENING AT:",socket_address)
# Socket Accept
while True:
client_socket,addr = server_socket.accept()
print('GOT CONNECTION FROM:',addr)
if client_socket:
vid = cv2.VideoCapture(0)

while(vid.isOpened()):
img,frame = vid.read()
a = pickle.dumps(frame)
message = struct.pack("Q",len(a))+a
client_socket.sendall(message)

cv2.imshow('TRANSMITTING VIDEO',frame)
key = cv2.waitKey(1) & 0xFF
if key ==ord('q'):
client_socket.close()

While in execution the both can communicate with TCP, with streaming video.

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